Write an equation in which the quadratic expression 2x^2-6x-8 equals 0. Show the expression in factored form, find the solution and explain what your solutions mean for the equation. Remember to show your work. Answer:(x-4)(x+1) Step-by-step explanation: 2x^2-6x-8 is given as 0 So 2x^2-6x-8=0 2(x^2-3x-4)=0 That is x^2-3x-4=0 It can also be written as x^2+(-4x+x)-4=0 Taking x common x(x-4)+1(x-4)=0 Taking x-4 common (x+1)(x-4)=0 That is Either x+1=0 or x-4=0 Therefore x=-1 or x=4 The significance is that if we put these values in the equation then the solution will be 0
A ball is thrown vertically upward at 10m/s. How high will it get, how long will it be in the air, and how fast will it be moving when it hits the ground? Step 1: Write the given Initial velocity (upward)= 10 m/s Step 2: Determine the formula/s that may be utilized For upward direction: For downward direction: Step 3: Find the maximum height of the ball Use the eq 3 for upward direction In order to find hte max height, use 0 m/s as the final velocity (0 m/s)²=(10 m/s)²-2(9.81 m/s²)(max height) 10²=2*9.81*max height The maximum height of the ball will reach is 5.10 meters. Step 4: Find the time it will stay in the air For upward motion, use equation 1 0 m/s= 10 m/s-(9.81 m/s²)(t upward) The time it will take to reach the maximum height is 1.02 sec. For downward motion, use equation 2 5.10 meters=(0 m/s)(t downward)+(1/2)(9.81 m/s²)(t downward)² The time it will take to reach the ground from maximum height is also 1.02 sec. The total time the ball will be in the air ...
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